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Proof step 11 from proof compatval-put (previous step)

okval(refval(r), ty) ∧ ( is_referencevalue(refval(r)) ∧ refval(r) .refval ≠ jvmref → refval(r) .refval -- _type ∈ st ∧ is_typevalue(st[refval(r) .refval -- _type]) ∧ is_reftype(st[refval(r) .refval -- _type] .type) ∧ (has_classtype(st[refval(r) .refval -- _type] .type) → tdname+∃(str, st[refval(r) .refval -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[refval(r) .refval -- _type] .type) → class+∃(str, st[refval(r) .refval -- _type] .type .class)) ∧ asgcomp(str, refval(r), ty, st)) ⊦ ty0 = void_type, r = jvmref, r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_reftype(st[r -- _type] .type) ∧ ( has_classtype(st[r -- _type] .type) → class∃(str, st[r -- _type] .type .jtelemtype .class) ∨ interface∃(str, st[r -- _type] .type .jtelemtype .class) ∨ is_predefined_class(st[r -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[r -- _type] .type) → class+∃(str, st[r -- _type] .type .class)) ∧ is_subtype(str, st[r -- _type] .type, ty)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
okval(refval(r), ty), r -- _type ∈ st, is_typevalue(st[r -- _type]), is_reftype(st[r -- _type] .type), asgcomp(str, refval(r), ty, st), r ∈ st, has_classtype(st[r -- _type] .type) → tdname+∃(str, st[r -- _type] .type .jtelemtype .class), is_classtype(st[r -- _type] .type) → class+∃(str, st[r -- _type] .type .class) ⊦ ty0 = void_type, r = jvmref, ( has_classtype(st[r -- _type] .type) → class∃(str, st[r -- _type] .type .jtelemtype .class) ∨ interface∃(str, st[r -- _type] .type .jtelemtype .class) ∨ is_predefined_class(st[r -- _type] .type .jtelemtype .class)) ∧ is_subtype(str, st[r -- _type] .type, ty)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st], [CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]