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Proof step 4 from proof compatval-put (previous step)

compat(str, refval(r), ty, st) ⊦ ty0 = void_type, ty = void_type, is_reftype(ty)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ compat(str, val, ty, st) ↔ okval(val, ty) ∧ ( is_referencevalue(val) ∧ val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ is_typevalue(st[val .refval -- _type]) ∧ is_reftype(st[val .refval -- _type] .type) ∧ (has_classtype(st[val .refval -- _type] .type) → tdname+∃(str, st[val .refval -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[val .refval -- _type] .type) → class+∃(str, st[val .refval -- _type] .type .class)) ∧ asgcomp(str, val, ty, st))

Rule argument

[crewrite-arg: value-compat , F , [st, ty, val, str] → [st, ty, refval(r), str] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ okval(refval(r), ty) ↔ ty = void_type ∨ is_reftype(ty)], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))], [CSIMPSEQ : ⊦ refval(r) .refval = r])], [EXTRATERMS : (st, ty, refval(r), str)]]