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Proof step 5 from proof compatval-put (previous step)

compat(str, refval(r), ty, st) ⊦ ty = void_type ∨ is_reftype(ty), ty0 = void_type

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
compat(str, refval(r), ty, st) ⊦ ty0 = void_type, ty = void_type, is_reftype(ty)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]