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Proof step 75 from proof contains-levelsubset (previous step)

level⊆(str, str0), ∃ tys. contains(str, ty ' + (tys + ty0)) ∧ ¬ dups(ty ' + tys) ⊦ contains(str0, ty, ty0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 74:
level⊆(str, str0), contains(str, ty ' + tys + ty0 ') ⊦ contains(str0, ty, ty0), dups(tys), ty ∈ tys

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (tys + tys0) + tys1 = tys + tys0 + tys1], [CSIMPSEQ : ⊦ dups(ty ' + tys) ↔ dups(tys) ∨ ty ∈ tys], [CSIMPSEQ : ⊦ tys + ty = tys + ty '])]]