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Proof step 76 from proof contains-levelsubset (previous step)

level⊆(str, str0), contains(str, ty, ty0) ⊦ contains(str0, ty, ty0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ contains(str, ty, ty0) ↔ (∃ tys. contains(str, ty ' + (tys + ty0)) ∧ ¬ dups(ty ' + tys))
Proof step 75:
level⊆(str, str0), ∃ tys. contains(str, ty ' + (tys + ty0)) ∧ ¬ dups(ty ' + tys) ⊦ contains(str0, ty, ty0)

Rule argument

[crewrite-arg: contains-type-def-nodups , F , [ty0, ty, str] → [ty0, ty, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (ty0, ty, str)]]