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Proof step 77 from proof contains-levelsubset (conclusion)

⊦ contains(str, ty, ty0) ∧ level⊆(str, str0) → contains(str0, ty, ty0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 76:
level⊆(str, str0), contains(str, ty, ty0) ⊦ contains(str0, ty, ty0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]