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Proof step 7 from proof contains-trans (previous step)

contains(str, ty0 ' + tys + ty1 '), contains(str, ty ' + tys0 + ty0 ') ⊦ dups(tys), ty0 ∈ tys, dups(tys0), ty ∈ tys0, ∃ tys1. contains(str, ty ' + tys1 + ty1 ')

User applied rule exists right

And obtained the following new goals

Proof step 6:
contains(str, ty0 ' + tys + ty1 '), contains(str, ty ' + tys0 + ty0 ') ⊦ dups(tys), ty0 ∈ tys, dups(tys0), ty ∈ tys0, contains(str, ty ' + (tys0 + (ty0 + tys)) + ty1 ')

Rule argument

[EXRARG : pos: right 5, [extquanttermlist: (tys0 + (ty0 + tys)) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (tys0 + (ty0 + tys))]]