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Proof step 8 from proof contains-trans (previous step)

contains(str, ty0 ' + tys + ty1 '), contains(str, ty ' + tys0 + ty0 ') ⊦ ∃ tys. contains(str, ty ' + (tys + ty1)), dups(tys), ty0 ∈ tys, dups(tys0), ty ∈ tys0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
contains(str, ty0 ' + tys + ty1 '), contains(str, ty ' + tys0 + ty0 ') ⊦ dups(tys), ty0 ∈ tys, dups(tys0), ty ∈ tys0, ∃ tys1. contains(str, ty ' + tys1 + ty1 ')

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ tys + ty = tys + ty '])]]