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Proof step 8 from proof pathex-levelsubset-equiv (previous step)

level⊆(str, str0) ⊦ path∃(str0, r, r0, st) ↔ path∃(str, r, r0, st), junkref(str, r, st)

User applied rule case distinction

And obtained the following new goals

Proof step 5:
path∃(str0, r, r0, st), level⊆(str, str0) ⊦ path∃(str, r, r0, st), junkref(str, r, st)
Proof step 7:
path∃(str, r, r0, st), level⊆(str, str0) ⊦ path∃(str0, r, r0, st), junkref(str, r, st)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]