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Proof step 9 from proof pathex-levelsubset-equiv (conclusion)

⊦ level⊆(str, str0) ∧ ¬ junkref(str, r, st) → (path∃(str0, r, r0, st) ↔ path∃(str, r, r0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
level⊆(str, str0) ⊦ path∃(str0, r, r0, st) ↔ path∃(str, r, r0, st), junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]