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Proof step 5 from proof pathex-levelsubset (previous step)

level⊆(str, str0), validrefs(str, r ' + refs1, mkclasstype(`java.lang.Object' .class), st) ⊦ r ' + refs1 ≠ [] ∧ (r ' + refs1) .first = r ∧ (r ' + refs1) .last = ((r ' + refs1) .first ' + refs1) .last ∧ validrefs(str0, r ' + refs1, mkclasstype(`java.lang.Object' .class), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
level⊆(str, str0), validrefs(str, r ' + refs1, mkclasstype(`java.lang.Object' .class), st) ⊦ validrefs(str0, r ' + refs1, mkclasstype(`java.lang.Object' .class), st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, references, c-08, ⊦ (r ' + refs) .first = r], [CSIMPNAMEDSEQ : list, references, a, ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPNAMEDSEQ : list, references, e, ⊦ r ' ≠ []], [CSIMPNAMEDSEQ : list, references, app-02-ant, ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []])]]