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Proof step 6 from proof pathex-levelsubset (previous step)

level⊆(str, str0), validrefs(str, r ' + refs1, mkclasstype(`java.lang.Object' .class), st) ⊦ ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = (refs .first ' + refs1) .last ∧ validrefs(str0, refs, mkclasstype(`java.lang.Object' .class), st)

User applied rule exists right

And obtained the following new goals

Proof step 5:
level⊆(str, str0), validrefs(str, r ' + refs1, mkclasstype(`java.lang.Object' .class), st) ⊦ r ' + refs1 ≠ [] ∧ (r ' + refs1) .first = r ∧ (r ' + refs1) .last = ((r ' + refs1) .first ' + refs1) .last ∧ validrefs(str0, r ' + refs1, mkclasstype(`java.lang.Object' .class), st)

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (r ' + refs1) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r ' + refs1)]]