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Proof step 15 from proof pathex-subset-equiv (previous step)

validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st0), st ⊆ st0 ⊦ refs = [], path∃(str, refs .first, refs .last, st), junkref(str, refs .first, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 14:
refs = r + refs0, validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st0), st ⊆ st0 ⊦ refs = [], path∃(str, r, refs .last, st), junkref(str, r, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [refs, r, refs0] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs, r, refs0)]]