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Proof step 16 from proof pathex-subset-equiv (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st0), st ⊆ st0 ⊦ path∃(str, r, r0, st), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st0), st ⊆ st0 ⊦ refs = [], path∃(str, refs .first, refs .last, st), junkref(str, refs .first, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]