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Proof step 15 from proof pathex-validrefs-in (previous step)

∃ refs0, refs1. refs = refs0 + (r0 + refs1), validrefs(str, r ' + refs, ty, st) ⊦ path∃(str, r, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
validrefs(str, r ' + refs1 + r0 ' + refs0, ty, st) ⊦ path∃(str, r, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r + refs = r ' + refs])]]