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Proof step 16 from proof pathex-validrefs-in (previous step)

r0 ∈ refs, validrefs(str, r ' + refs, ty, st) ⊦ path∃(str, r, r0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r ∈ refs ↔ (∃ refs0, refs1. refs = refs0 + (r + refs1))
Proof step 15:
∃ refs0, refs1. refs = refs0 + (r0 + refs1), validrefs(str, r ' + refs, ty, st) ⊦ path∃(str, r, r0, st)

Rule argument

[x0lemmaarg: spec-name: list instance-name: references lemma-name: In antecedent: succedent: r ∈ refs ↔ (∃ refs0, refs1. refs = refs0 + (r + refs1)) substlist: [refs, r] → [refs, r0] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((0, 0, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (refs, r0)]]