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Proof step 29 from proof validrefs-has-null (previous step)

r ≠ jvmref, validrefs(str, (r ' + acc) + refs0, ty, st), jvmref ∈ acc, ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ refs0 = [], jvmref = r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
jvmref ∈ acc, validrefs(str, (r ' + acc) + refs0, ty, st), ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ r = jvmref, refs0 = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]