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Proof step 30 from proof validrefs-has-null (previous step)

validrefs(str, (r ' + acc) + refs0, ty, st), jvmref ∈ acc, ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ refs0 = [], jvmref = r

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ r = jvmref → (validrefs(str, r ' + refs, ty, st) ↔ refs = [])
Proof step 29:
r ≠ jvmref, validrefs(str, (r ' + acc) + refs0, ty, st), jvmref ∈ acc, ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ refs0 = [], jvmref = r

Rule argument

[crewrite-arg: validrefs-null , F , [st, ty, refs, r, str] → [st, ty, acc + refs0, r, str] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])], [EXTRATERMS : (st, ty, acc + refs0, r, str)]]