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Proof step 10 from proof junkref-put-norefval (previous step)

is_fskey(sk), okval(val, sk .fs .type), junkrefs(str, r ' + refs1, (st[r1 -- sk, val][r -- _type]) .type, st[r1 -- sk, val]) ⊦ sk = _length, sk .fs .type = void_type, is_referencevalue(val), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
sk = fs ', is_fskey(sk), okval(val, fs .type), junkrefs(str, r ' + refs1, (st[r1 -- sk, val][r -- _type]) .type, st[r1 -- sk, val]) ⊦ sk = _length, fs .type = void_type, is_referencevalue(val), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk, fs)]]