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Proof step 11 from proof junkref-put-norefval (previous step)

refs = r + refs1, junkrefs(str, refs, (st[r1 -- sk, val][r -- _type]) .type, st[r1 -- sk, val]), is_fskey(sk), okval(val, sk .fs .type) ⊦ sk = _length, sk .fs .type = void_type, refs = [], is_referencevalue(val), ∃ refs0. refs0 ≠ [] ∧ refs0 .first = r ∧ junkrefs(str, refs0, st[r -- _type] .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
is_fskey(sk), okval(val, sk .fs .type), junkrefs(str, r ' + refs1, (st[r1 -- sk, val][r -- _type]) .type, st[r1 -- sk, val]) ⊦ sk = _length, sk .fs .type = void_type, is_referencevalue(val), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]