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Proof step 4 from proof levelsubset-is-array (previous step)

level⊆(str, str0), is_array(r, st), type∃(str, st[r -- _type] .type) ⊦ st[r -- _type] .type .jtelemtype = void_type, st[r -- _type] .type .jtelemtype = abstract_type, is_array(str0, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_array(str, r, st) ↔ type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st)
Proof step 3:
⊦ type∃(str, ty) ∧ ¬ type∃(str0, ty) → ¬ level⊆(str, str0)

Rule argument

[speclemmaarg: , is_array(str, r, st) ↔ type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st) ,[st, r, str] → [st, r, str0] ,F ,okfuns , ,is-real-array-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r, str0)]]