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Proof step 5 from proof levelsubset-is-array (previous step)

type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st), level⊆(str, str0) ⊦ is_array(str0, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
level⊆(str, str0), is_array(r, st), type∃(str, st[r -- _type] .type) ⊦ st[r -- _type] .type .jtelemtype = void_type, st[r -- _type] .type .jtelemtype = abstract_type, is_array(str0, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]