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Proof step 4 from proof levelsubset-is-obj (previous step)

level⊆(str, str0), is_obj(r, st), class+∃(str, st[r -- _type] .type .class) ⊦ is_abstract(st[r -- _type] .type .class), class+∃(str0, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ class+∃(str, class) ∧ level⊆(str, str0) → (¬ class+∃(str0, class) ↔ false)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]