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Proof step 5 from proof levelsubset-is-obj (previous step)

level⊆(str, str0), is_obj(r, st), class+∃(str, st[r -- _type] .type .class) ⊦ is_abstract(st[r -- _type] .type .class), is_obj(str0, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)
Proof step 4:
level⊆(str, str0), is_obj(r, st), class+∃(str, st[r -- _type] .type .class) ⊦ is_abstract(st[r -- _type] .type .class), class+∃(str0, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)

Rule argument

[speclemmaarg: , is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st) ,[st, r, str] → [st, r, str0] ,F ,addfuns , ,is-real-object-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r, str0)]]