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Proof step 18 from proof same-subclasses-is-array (previous step)

has_classtype(st[r -- _type] .type), (∀ class0. class∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → class∃(str, class0)) ∧ (∀ class0. interface∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → interface∃(str, class0)), is_array(r, st), tdname+∃(str0, st[r -- _type] .type .jtelemtype .class) ⊦ st[r -- _type] .type .jtelemtype = abstract_type, st[r -- _type] .type .jtelemtype = void_type, tdname+∃(str, st[r -- _type] .type .jtelemtype .class)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
tdname+∃(str0, st[r -- _type] .type .jtelemtype .class), is_array(r, st), has_classtype(st[r -- _type] .type), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → class∃(str, class0) ⊦ st[r -- _type] .type .jtelemtype = void_type, st[r -- _type] .type .jtelemtype = abstract_type, tdname+∃(str, st[r -- _type] .type .jtelemtype .class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]