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Proof step 19 from proof same-subclasses-is-array (previous step)

has_classtype(st[r -- _type] .type), same-subclasses(st[r -- _type] .type .jtelemtype .class, str, str0), is_array(r, st), tdname+∃(str0, st[r -- _type] .type .jtelemtype .class) ⊦ st[r -- _type] .type .jtelemtype = abstract_type, st[r -- _type] .type .jtelemtype = void_type, tdname+∃(str, st[r -- _type] .type .jtelemtype .class)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ same-subclasses(class, str, str0) ↔ (∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0)) ∧ (∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0))
Proof step 18:
has_classtype(st[r -- _type] .type), (∀ class0. class∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → class∃(str, class0)) ∧ (∀ class0. interface∃(str0, class0) ∧ class0 ≤ st[r -- _type] .type .jtelemtype .class → interface∃(str, class0)), is_array(r, st), tdname+∃(str0, st[r -- _type] .type .jtelemtype .class) ⊦ st[r -- _type] .type .jtelemtype = abstract_type, st[r -- _type] .type .jtelemtype = void_type, tdname+∃(str, st[r -- _type] .type .jtelemtype .class)

Rule argument

[crewrite-arg: same-subclasses-one-def , F , [str0, str, class] → [str0, str, st[r -- _type] .type .jtelemtype .class] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str0, str, st[r -- _type] .type .jtelemtype .class)]]