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Proof step 4 from proof same-subclasses-tdnameex-01 (previous step)

class0 ≤ class, tdname+∃(str0, class0), same-subclasses(class, str, str0) ⊦ tdname+∃(str, class0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ tdname+∃(str, class) ↔ tdname∃(str, class) ∨ is_predefined_class(class)
Proof step 3:
class0 ≤ class, tdname+∃(str0, class0), same-subclasses(class, str, str0) ⊦ tdname∃(str, class0) ∨ is_predefined_class(class0)

Rule argument

[speclemmaarg: , tdname+∃(str, class) ↔ tdname∃(str, class) ∨ is_predefined_class(class) ,[class, str] → [class0, str] ,F ,typefuns , ,tdname+ex-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (class0, str)]]