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Proof step 5 from proof same-subclasses-tdnameex-01 (conclusion)

⊦ ¬ tdname+∃(str, class0) ∧ tdname+∃(str0, class0) ∧ class0 ≤ class → ¬ same-subclasses(class, str, str0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
class0 ≤ class, tdname+∃(str0, class0), same-subclasses(class, str, str0) ⊦ tdname+∃(str, class0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]