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Proof step 5 from proof same-subclasses-tdnameex-02 (previous step)

class∃(str0, class0) ∨ interface∃(str0, class0), class0 ≤ class, ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ tdname∃(str, class0)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
class∃(str0, class0), class0 ≤ class, ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ tdname∃(str, class0)
Proof step 4:
interface∃(str0, class0), class0 ≤ class, ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ tdname∃(str, class0)

Rule argument

[CASEDARG : pos: left 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]