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Proof step 6 from proof same-subclasses-tdnameex-02 (previous step)

tdname∃(str0, class0), class0 ≤ class, ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ tdname∃(str, class0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ tdname∃(str, class) ↔ class∃(str, class) ∨ interface∃(str, class)
Proof step 5:
class∃(str0, class0) ∨ interface∃(str0, class0), class0 ≤ class, ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ tdname∃(str, class0)

Rule argument

[speclemmaarg: ,tdname∃(str, class) ↔ class∃(str, class) ∨ interface∃(str, class) ,[class, str] → [class0, str0] ,F ,typefuns , ,tdnameex-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (class0, str0)]]