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Proof step 6 from proof validref-put-norefval-01 (previous step)

okval(val, sk .fs .type), is_fskey(sk), validref(str, r, ty, st) ⊦ sk .fs .type = void_type, sk = _length, is_referencevalue(val), validref(str, r, ty, st[r1 -- sk, val])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
sk = fs ', okval(val, fs .type), is_fskey(sk), validref(str, r, ty, st) ⊦ fs .type = void_type, sk = _length, is_referencevalue(val), validref(str, r, ty, st[r1 -- sk, val])

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk, fs)]]