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Proof step 7 from proof validref-put-norefval-01 (conclusion)

⊦ ¬ is_referencevalue(val) ∧ validref(str, r, ty, st) ∧ is_fskey(sk) ∧ okval(val, sk .fs .type) ∧ sk .fs .type ≠ void_type ∧ sk ≠ _length → validref(str, r, ty, st[r1 -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
okval(val, sk .fs .type), is_fskey(sk), validref(str, r, ty, st) ⊦ sk .fs .type = void_type, sk = _length, is_referencevalue(val), validref(str, r, ty, st[r1 -- sk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]