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Proof step 10 from proof validrefkeynotnull-refval-in (previous step)

r -- sk ∈ st ∧ validrefvalnotnull(str, st[r -- sk], ty, st) ⊦ st[r -- sk] .refval ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]