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Proof step 9 from proof validrefkeynotnull-refval-in (previous step)

r -- sk ∈ st, validrefvalnotnull(str, st[r -- sk], ty, st), r ∈ st ⊦ st[r -- sk] .refval ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ validrefvalnotnull(str, val, ty, st) ↔ is_referencevalue(val) ∧ validrefnotnull(str, val .refval, ty, st)
Proof step 8:
r -- sk ∈ st, is_referencevalue(st[r -- sk]) ∧ validrefnotnull(str, st[r -- sk] .refval, ty, st), r ∈ st ⊦ st[r -- sk] .refval ∈ st

Rule argument

[crewrite-arg: validrefvalnotnull-def , F , [st, ty, val, str] → [st, ty, st[r -- sk], str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, ty, st[r -- sk], str)]]