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Proof step 24 from proof validrefkeynotnull-subset (previous step)

st[rk] = refval(r), rk ∈ st1, st ⊆ st1, rk ∈ st, r ≠ jvmref ∧ validref(str, r, ty, st) ⊦ r = jvmref, is_referencevalue(st1[rk]) ∧ validrefnotnull(str, st1[rk] .refval, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
st[rk] = refval(r), validref(str, r, ty, st), rk ∈ st, st ⊆ st1, rk ∈ st1 ⊦ r = jvmref, is_referencevalue(st1[rk]) ∧ validrefnotnull(str, st1[rk] .refval, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]