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Proof step 25 from proof validrefkeynotnull-subset (previous step)

st[rk] = refval(r), rk ∈ st1, st ⊆ st1, rk ∈ st, validrefnotnull(str, r, ty, st) ⊦ r = jvmref, is_referencevalue(st1[rk]) ∧ validrefnotnull(str, st1[rk] .refval, ty, st1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ validrefnotnull(str, r, ty, st) ↔ r ≠ jvmref ∧ validref(str, r, ty, st)
Proof step 24:
st[rk] = refval(r), rk ∈ st1, st ⊆ st1, rk ∈ st, r ≠ jvmref ∧ validref(str, r, ty, st) ⊦ r = jvmref, is_referencevalue(st1[rk]) ∧ validrefnotnull(str, st1[rk] .refval, ty, st1)

Rule argument

[crewrite-arg: validrefnotnull-def , F , [st, ty, r, str] → [st, ty, r, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, ty, r, str)]]