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Proof step 11 from proof validreflist-addarray (previous step)

validreflist(str, vals1, ty1, st), validref(str, val .refval, ty1, st), is_referencevalue(val), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, val ' + vals1, ty1, addarray(newref(st), ty, vals0, st))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 10:
val = refval(r), validreflist(str, vals1, ty1, st), validref(str, r, ty1, st), is_referencevalue(val), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, val ' + vals1, ty1, addarray(newref(st), ty, vals0, st))

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [val, r] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r)]]