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Proof step 12 from proof validreflist-addarray (previous step)

is_referencevalue(val) ∧ validref(str, val .refval, ty1, st) ∧ validreflist(str, vals1, ty1, st), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, val ' + vals1, ty1, addarray(newref(st), ty, vals0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
validreflist(str, vals1, ty1, st), validref(str, val .refval, ty1, st), is_referencevalue(val), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, val ' + vals1, ty1, addarray(newref(st), ty, vals0, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]