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Proof step 5 from proof validrefnotnull-subset (previous step)

st ⊆ st1, validref(str, r, ty, st) ⊦ r = jvmref, validref(str, r, ty, st1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ validref(str, r, ty, st) ∧ st ⊆ st1 → validref(str, r, ty, st1)

Rule argument

[crewrite-arg: validref-subset , F , [str, r, ty, st, st1] → [str, r, ty, st, st1] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r, ty, st, st1)]]