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Proof step 6 from proof validrefnotnull-subset (previous step)

r ≠ jvmref ∧ validref(str, r, ty, st), st ⊆ st1 ⊦ r = jvmref, validref(str, r, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
st ⊆ st1, validref(str, r, ty, st) ⊦ r = jvmref, validref(str, r, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]