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Proof step 47 from proof addarrays-auto-22 (previous step)

¬ (2 ' + 2 ' = [] ∨ n→i(# refs) ≠ countrefs(2 ' + 2 ') ∨ ¬ posints(2 ' + 2 ')) ⊦ # refs = 3, addarrays(refs, ty, 2 ' + 2 ', 0, st) = st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 46:
n→i(# refs) = countrefs(2 ' + 2 ') ⊦ # refs = 3, addarrays(refs, ty, 2 ' + 2 ', 0, st) = st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ posints(i ') ↔ 0 ≤ i], [CSIMPSEQ : ⊦ posints(i ' + ints) ↔ 0 ≤ i ∧ posints(ints)], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ i ' + ints ≠ []])]]