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Proof step 48 from proof addarrays-auto-22 (previous step)

⊦ # refs = 3, addarrays(refs, ty, 2 ' + 2 ', 0, st) = st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 43:
⊦ ints = [] ∨ n→i(# refs) ≠ countrefs(ints) ∨ ¬ posints(ints) → addarrays(refs, ty, ints, i, st) = st
Proof step 47:
¬ (2 ' + 2 ' = [] ∨ n→i(# refs) ≠ countrefs(2 ' + 2 ') ∨ ¬ posints(2 ' + 2 ')) ⊦ # refs = 3, addarrays(refs, ty, 2 ' + 2 ', 0, st) = st

Rule argument

[crewrite-arg: addarrays-empty , F , [st, i, ints, ty, refs] → [st, 0, 2 ' + 2 ', ty, refs] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, 0, 2 ' + 2 ', ty, refs)]]