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Proof step 11 from proof countrefs2-pos (previous step)

i ≤ 0, countrefs2(i ' + ints0) < 0, 0 ≤ countrefs2(ints0) ⊦ ints0 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ints ≠ [] ∧ 1 ≤ i → countrefs2(i ' + ints) = i + i * countrefs2(ints)
Proof step 10:
¬ (ints0 ≠ [] ∧ 1 ≤ i), i ≤ 0, countrefs2(i ' + ints0) < 0, 0 ≤ countrefs2(ints0) ⊦ ints0 = []

Rule argument

[crewrite-arg: countrefs2-01, F, [ints, i] → [ints0, i]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 1 ≤ i ↔ 0 < i], [CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)])], [EXTRATERMS : (ints0, i)]]