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Proof step 12 from proof countrefs2-pos (previous step)

¬ (ints0 ≠ [] ∧ 0 < i), 0 ≤ countrefs2(ints0), countrefs2(i ' + ints0) < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ countrefs2(i ') = 0
Proof step 11:
i ≤ 0, countrefs2(i ' + ints0) < 0, 0 ≤ countrefs2(ints0) ⊦ ints0 = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j], [CSIMPFORWARD : ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0], [CSIMPFORWARD : ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ ints + [] = ints], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i])]]