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Theorem eqref
⊦ eqref(r, r0, st, st0) ↔ r = jvmref ∧ r0 = jvmref ∨ r ≠ jvmref ∧ r0 ≠ jvmref ∧ (∀ sk. (r -- sk ∈ st ↔ r0 -- sk ∈ st0) ∧ (r -- sk ∈ st → eqval(st[r -- sk], st0[r0 -- sk], st, st0)))
Type: An axiom
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: No