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Proof step 10 from proof exactarray-out (conclusion)

⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ rk .ref ≠ val .refval → (exactarray(val, ty, i, st[rk, val0]) ↔ exactarray(val, ty, i, st))
Proof step 9:
¬ _out .ref ≠ val .refval ⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

Rule argument

[crewrite-arg: exactarray-put-07 , F , [val0, rk, st, i, ty, val] → [val0, _out, st, i, ty, val] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val0, _out, st, i, ty, val)]]