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Proof step 9 from proof exactarray-out (previous step)

¬ _out .ref ≠ val .refval ⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
_out .ref = val .refval ⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]