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Proof step 8 from proof exactarray-out (previous step)

_out .ref = val .refval ⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
_out = r -- sk, r = val .refval ⊦ exactarray(val, ty, i, st[_out, val0]) ↔ exactarray(val, ty, i, st)

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [_out, r, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (_out, r, sk)]]