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Proof step 5 from proof exactref-put-01 (previous step)

r ∈ st, r ≠ jvmref → r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ st[r -- _type] .type = ty ⊦ rk .ref = r, exactreftype(refval(r), ty, st[rk, val])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
rk = r0 -- sk, r ∈ st, r ≠ jvmref → r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ st[r -- _type] .type = ty ⊦ r0 = r, exactreftype(refval(r), ty, st[rk, val])

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r0, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r0, sk)]]