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Proof step 6 from proof exactref-put-01 (conclusion)

⊦ rk .ref ≠ r ∧ ¬ exactreftype(refval(r), ty, st[rk, val]) → ¬ exactreftype(refval(r), ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ exactreftype(val, ty, st) ↔ is_referencevalue(val) ∧ val .refval ∈ st ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ is_typevalue(st[val .refval -- _type]) ∧ st[val .refval -- _type] .type = ty)
Proof step 5:
r ∈ st, r ≠ jvmref → r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ st[r -- _type] .type = ty ⊦ rk .ref = r, exactreftype(refval(r), ty, st[rk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]